6m^2=13m=28

Solution for 6m^2=13m=28 equation:

6m^2=13m=28

We move all terms to the left:

6m^2-(13m)=0

a = 6; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·6·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*6}=\frac{0}{12}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*6}=\frac{26}{12}
=2+1/6
$